{"id":5828,"date":"2025-04-28T15:14:26","date_gmt":"2025-04-28T13:14:26","guid":{"rendered":"https:\/\/www.dclabs.lt\/dainiaus\/?p=5828"},"modified":"2025-04-28T15:14:26","modified_gmt":"2025-04-28T13:14:26","slug":"automobilinio-grotuvo-ekrano-uztemdymas","status":"publish","type":"post","link":"https:\/\/www.dclabs.lt\/dainiaus\/automobilinio-grotuvo-ekrano-uztemdymas\/","title":{"rendered":"Automobilinio grotuvo ekrano u\u017etemdymas"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Labai trumpas, greitas projektukas, atsirad\u0119s d\u0117l paprasto poreikio. Ma\u0161inose be dienos \u0161viesos lemp\u0173 privaloma dienos metu va\u017eiuoti \u012fjungus artim\u0173j\u0173 \u0161vies\u0173 lempas, tod\u0117l audio sistemos grotuvas galvoja, kad dabar naktis ir pritemdo savo displ\u0117j\u0173. Saul\u0117t\u0105 dien\u0105 jame beveik nieko ir nebesimato, plius \u012fjungiamas naktinis re\u017eimas, pavyzd\u017eiui, mygtuk\u0173 ap\u0161vietimas. Tas ypa\u010d galioja pakeitus gamyklin\u0117 automobilio grotuv\u0105 \u012f kitok\u012f, pavyzd\u017eiui, su Android OS ir papildomais funkcionalumais. Taigi, reikia prietaisiuko, kuris reaguot\u0173 \u012f ap\u0161vietim\u0105 ir pagal tai paduot\u0173 signal\u0105 \u012f atitinkam\u0105 grotuvo kontakt\u0105. Turim tiksl\u0105, tik suformuluokime u\u017eduot\u012f:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Prietaisas turi reaguoti \u012f ap\u0161viestum\u0105, pagal tai valdyti atitinkam\u0105 grotuvo kontakt\u0105;<\/li>\n\n\n\n<li>Maitinimas nuo 11 V iki 16 V;<\/li>\n\n\n\n<li>Grotuvo valdymas turi b\u016bti universalus &#8211; nes ne\u017einome vis\u0173 \u012fmanom\u0173 grotuv\u0173 variant\u0173;<\/li>\n\n\n\n<li>Ap\u0161viestumo jautrumas turi b\u016bti reguliuojamas;<\/li>\n\n\n\n<li>Genialumas paprastume, tai gal neprad\u0117kim programuoti mikrovaldikli\u0173;<\/li>\n\n\n\n<li>Prietaisas turi b\u016bti saugus naudoti.<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Tiek kol kas u\u017etenka, pradedame konstruoti schem\u0105.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-large\"><a href=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/image.png\" target=\"_blank\" rel=\" noreferrer noopener\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"451\" src=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/image-1024x451.png\" alt=\"\" class=\"wp-image-5833\" srcset=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/image-1024x451.png 1024w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/image-300x132.png 300w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/image-768x338.png 768w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/image-1536x677.png 1536w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/image-2048x902.png 2048w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/a><\/figure>\n<\/div>\n\n\n<p class=\"wp-block-paragraph\">Ok, dabar kaip \u010dia viskas padaryta ir veikia. Kaip visada, i\u0161 kair\u0117s \u012f de\u0161in\u0119. Nedidel\u0117 keturi\u0173 kontakt\u0173 jungtel\u0117, maitinimo pliusas po degimo (KL15+), pastovus minusas (KL31), 12V i\u0161\u0117jimas ir minuso i\u0161\u0117jimas. Kod\u0117l tiek daug ? Ogi universalumui, valdymas gali b\u016bti arba pliusiniu signalu arba minusu. Normalioje pad\u0117tyje \u0161iuose i\u0161\u0117jimuose nieko, laido galas kaba ore arba &#8222;float&#8221; <img decoding=\"async\" draggable=\"false\" class=\"eedee-emoji\" src=\"https:\/\/s.w.org\/images\/core\/emoji\/12.0.0-1\/svg\/1f601.svg\" alt=\"\ud83d\ude01\">. Toliau saugumas, saugiklis F1, 1A tur\u0117t\u0173 b\u016bti per akis visose situacijose, tu pa\u010diu ir pakankamai saugu. \u012e\u0117jimo kondensatorius C1 &#8211; kod\u0117l 1 uF ? Nes toki\u0173 daug turiu, principe gali b\u016bti ir kitoks. Truput\u012f stabilizuoja \u012feinant\u012f maitinim\u0105, sugaudo trukd\u017eius jei koki\u0173 yra. Toliau &#8222;aktyvusis elementas&#8221;, 1M\u2126 daugias\u016bkis potenciometras R2 ir fotorezistorius LDR1. Potenciometras daugias\u016bkis tikslesniam reguliavimui, o 1M\u2126 nes tokia maksimali var\u017ea leis prijungti prakti\u0161kai bet kur\u012f fotorezistori\u0173 ir sureguliuoti teisingam veikimui. \u0160ita schemos dalis veikia taip &#8211; kai \u0161viesu, fotorezistoriaus var\u017ea ma\u017ea, o potenciometras taip sureguliuotas, kad jo var\u017ea palyginus su fotorezistoriaus var\u017ea didel\u0117, tod\u0117l ribiniu atveju schema tampa tokia:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><a href=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/image-1.png\"><img loading=\"lazy\" decoding=\"async\" width=\"551\" height=\"792\" src=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/image-1.png\" alt=\"\" class=\"wp-image-5838\" style=\"width:160px;height:auto\" srcset=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/image-1.png 551w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/image-1-209x300.png 209w\" sizes=\"auto, (max-width: 551px) 100vw, 551px\" \/><\/a><\/figure>\n<\/div>\n\n\n<p class=\"wp-block-paragraph\">Kai tamsu, fotorezistoriaus var\u017ea didel\u0117, sakykim 100 k\u2126, o potenciometro var\u017ea tampa palyginti ma\u017ea:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><a href=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-10563-5.png\"><img loading=\"lazy\" decoding=\"async\" width=\"551\" height=\"737\" src=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-10563-5.png\" alt=\"\" class=\"wp-image-5844\" style=\"width:158px;height:auto\" srcset=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-10563-5.png 551w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-10563-5-224x300.png 224w\" sizes=\"auto, (max-width: 551px) 100vw, 551px\" \/><\/a><\/figure>\n<\/div>\n\n\n<p class=\"wp-block-paragraph\">Analizuoti tokias ribines pad\u0117tis lengviau, nors realiai ten nebus nei visai minusas, nei visai pliusas, nes bus tam tikros var\u017eos tiek fotorezistoriuje, tiek ir potenciometre, tod\u0117l b\u016bt\u0173 geriau analizuoti \u0161it\u0105 por\u0105 kaip var\u017ein\u012f dalikl\u012f, bet u\u017etai taip papras\u010diau suprasti kod\u0117l \u0161ita pora apskritai veikia. Taigi, pirmu atveju R3 gauna pseudo gryn\u0105 minus\u0105, antru atveju gauna pseudo plius\u0105. Pasikartosiu, tur\u0117kime galvoje, kad ten bus ka\u017ekokia tarpin\u0117 \u012ftampos vert\u0117, tarp 0V ir VCC, tik suveikimas atsitiks, kai ta \u012ftampa bus auk\u0161\u010diau arba \u017eemiau tam tikros slenkstin\u0117s vert\u0117s, kuri priklauso nuo tranzistoriaus. Toliau, R3 su Zenerio diodu, dar vadinamu stabilitronu, sudaro silpnasrov\u012f maitinimo \u0161altin\u012f. Jo reikia tam, kad tranzistoriaus Q1 baz\u0117s &#8211; nes baz\u0117s maksimal\u012f \u012ftampa V<sub>EBO<\/sub> = 10V. <a href=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/BCV27.pdf\" target=\"_blank\" rel=\"noreferrer noopener\">Tranzistoriaus apra\u0161ymas yra \u010dia<\/a>. O ma\u0161inoje tikrai bus daugiau, net iki 15V. Taigi, stabilitronas apriboja maksimali\u0105 \u012ftamp\u0105. Kokia ji turi b\u016bti ? Apra\u0161yme para\u0161yta, kad V<sub>BEsat<\/sub> = 1,5V, tai yra tranzistorius pilnai atidarytas, kai \u012ftampa tarp baz\u0117s ir emiterio yra 1,5V arba daugiau, bet ne daugiau 10V, nes bus p\u0161\u0161\u0161 ir pasimatys tai, i\u0161 ko padaryta visa elektronika &#8211; d\u016bmai. D\u0117l stabilumo, garantuoto tranzistoriaus atidarymo ir toli nuo pavojingos maksimalios \u012ftampos imame pus\u0119 maksimalios \u012ftampos vert\u0117s, tarkim 5V. Tikt\u0173, principe, bet kas nuo 1,5V iki koki\u0173 9V&#8230; Ok, ok, dar plius, kad tur\u0117jau 5V stabilitron\u0173, tai pasirinkimas dar supaprast\u0117jo. Tur\u0117dami tiek duomen\u0173, galime pabandyti paskai\u010diuoti stabilitrono ir jo balastinio rezistoriaus parametrus. I\u0161eitiniai duomenys skai\u010diavimui:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Maksimali \u012ftampa &#8211; 15V<\/li>\n\n\n\n<li>Minimali \u012ftampa &#8211; 8V (nes m\u016bs\u0173 R2-LDR1 daliklis gali duoti ir ma\u017eiau nei 12V, tai paimu toki\u0105 \u012ftamp\u0105, gali b\u016bti ir kita, bet jeigu daliklio \u012ftampa bus didesn\u0117 u\u017e 1,4V, stabilitronas nieko neveiks, o tranzistorius \u012fsijungs)<\/li>\n\n\n\n<li>Reikiama \u012ftampa i\u0161\u0117jime &#8211; 5V<\/li>\n\n\n\n<li>Apkrovos srov\u0117 &#8211; \u010dia toks sud\u0117tingesnis parametras, bet i\u0161 tranzistoriaus apra\u0161ymo pikin\u0117 baz\u0117s rov\u0117 I<sub>BM<\/sub> = 100 mA, plius ka\u017ekiek srov\u0117s kondensatoriaus C2 krovimui, bet tiek srov\u0117s neduosim, duokime, tarkim tre\u010ddal\u012f &#8211; I<sub>max<\/sub> = 30 mA. I<sub>z_min<\/sub> pana\u0161iai 10% nuo visos srov\u0117s, tai 0,003 A.<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-mathml-mathmlblock\">\\[ I_{total} = I_{Zmin} + I_{L} \\]<script id=\"wp-hooks-js\" src=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-includes\/js\/dist\/hooks.min.js?ver=f0f188028580e8dc1255\"><\/script>\n<script id=\"wp-i18n-js\" src=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-includes\/js\/dist\/i18n.min.js?ver=1dfe7db3940c23ea9216\"><\/script>\n<script id=\"wp-i18n-js-after\">\nwp.i18n.setLocaleData( { 'text direction\\u0004ltr': [ 'ltr' ] } );\n\/\/# sourceURL=wp-i18n-js-after\n<\/script>\n<script  async id=\"mathjax-js\" src=\"https:\/\/cdnjs.cloudflare.com\/ajax\/libs\/mathjax\/2.7.7\/MathJax.js?config=TeX-MML-AM_CHTML\"><\/script>\n<\/div>\n\n\n\n<div class=\"wp-block-mathml-mathmlblock\">\\[ I_{total} = 0,003 + 0,03 = 0,033 A\\]<\/div>\n\n\n\n<div class=\"wp-block-mathml-mathmlblock\">\\[ R = \\frac{U_{Supl} &#8211; U_{Z}}{I_{total}}\\]<\/div>\n\n\n\n<div class=\"wp-block-mathml-mathmlblock\">\\[ R = \\frac{15 &#8211; 5}{0,033}=303,03\u2126\\]<\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Paimkime, kad rezistorius bus 300 \u2126.<\/p>\n\n\n\n<div class=\"wp-block-mathml-mathmlblock\">\\[ P_{R} = (U_{Supl} &#8211; U_{Z}) \\cdot I_{total}\\]<\/div>\n\n\n\n<div class=\"wp-block-mathml-mathmlblock\">\\[ P_{R} = (15 &#8211; 5) \\cdot 0,033 = 0,33W = 330 mW\\]<\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Rezistoriaus galingumas apie 330 mW.<\/p>\n\n\n\n<div class=\"wp-block-mathml-mathmlblock\">\\[ P_{D} = U_{Z} \\cdot \\left( I_{max} &#8211; I_{min} + I_{D} \\right)\\]<\/div>\n\n\n\n<div class=\"wp-block-mathml-mathmlblock\">\\[ P_{D} = 5 \\cdot \\left( 0,03 &#8211; 0,03 + 0,003 \\right)=0,015W = 15 mW\\]<\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Stabilitrono galingumo skai\u010diavimui I<sub>max<\/sub> ir I<sub>min<\/sub> imu vienodus, nors gal apkrovos srov\u0117 ir nebus visada vienoda ir stabili, bet turint tok\u012f didel\u012f atsargos koeficient\u0105, many\u010diau taip gan\u0117tinai saugu. O skai\u010diavimas gerokai supaprast\u0117ja.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Toliau, rezistorius R4, ribojantis kondensatoriaus \u012fsikrovimo greit\u012f ir baz\u0117s srov\u0119. Rezistoriaus skai\u010diavimas toks pusiau \u0161amanizmas, su visokiom Betom ir pana\u0161iai, o bet ta\u010diau, \u0161tai:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Valdymo \u012ftampa U<sub>ctrl<\/sub> = 5V<\/li>\n\n\n\n<li>Kolektoriaus maksimali srov\u0117 I<sub>C<\/sub> = 0,5A<\/li>\n\n\n\n<li>Koeficientas \u03b2 = 10000<\/li>\n\n\n\n<li>\u012etampos kritimas PN sand\u016broje U<sub>pnp_drop<\/sub> = 0,7V<\/li>\n\n\n\n<li>Maksimali baz\u0117s srov\u0117 I<sub>b_max<\/sub> = 100mA = 0,1A<\/li>\n<\/ul>\n\n\n\n<div class=\"wp-block-mathml-mathmlblock\">\\[I_{c} = \\beta \\cdot I_{b}\\]<\/div>\n\n\n\n<p class=\"wp-block-paragraph\">I\u0161 \u010dia:<\/p>\n\n\n\n<div class=\"wp-block-mathml-mathmlblock\">\\[I_{b} = \\frac{I_{c}}{\\beta} =\\frac{0,5}{10000} = 0,00005A = 0,05 mA\\]<\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Taigi, leid\u017eiant per baz\u0119 bent 0,05 mA, kolektoriaus-emiterio srov\u0117 tur\u0117t\u0173 b\u016bti galima maksimali, pus\u0117 ampero.<\/p>\n\n\n\n<div class=\"wp-block-mathml-mathmlblock\">\\[U_{ctrl} = I \\cdot R\\]<\/div>\n\n\n\n<div class=\"wp-block-mathml-mathmlblock\">\\[R_{max} = \\frac{U_{ctrl} &#8211; U_{p-n\\_drop}}{I_{b}}\\]<\/div>\n\n\n\n<div class=\"wp-block-mathml-mathmlblock\">\\[R_{max} = \\frac{5 &#8211; 0,7}{0,00005}= 86000\u2126 = 86 k\u2126\\] <\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Turime, kad maksimali baz\u0117s rezistoriaus var\u017ea yra 86 k\u2126, bet patikimam ir greitam tranzistoriaus atidarymui, galime didinti srov\u0119, nes turime 20 mA limit\u0105. Suma\u017einus var\u017e\u0105 20 kart\u0173, srov\u0117 padid\u0117s 20 kart\u0173, tai bus 1 mA. Tur\u0117t\u0173 pakakti tranzistoriaus atidarymui, kad jis dirbt\u0173 rakto re\u017eimu, o ne linijiniu. B\u016bt\u0173 galima dar ma\u017einti var\u017e\u0105, tarkim, suma\u017einus 200 kart\u0173, iki 430\u2126, srov\u0117 b\u016bt\u0173 10 mA. Bet laim\u0117jo 4700 \u2126 rezistorius, nes tok\u012f tur\u0117jau po ranka, srov\u0117 tur\u0117t\u0173 b\u016bti apie 1 mA. Tas pats rezistorius dar ir stabdo kondensatorius C2 \u012fsikrovim\u0105. Kondensatorius pasikraus per laik\u0105 \u03c4 (Tau):<\/p>\n\n\n\n<div class=\"wp-block-mathml-mathmlblock\"><\/div>\n\n\n\n<div class=\"wp-block-mathml-mathmlblock\">\\[ \\tau = R \\cdot C\\]<\/div>\n\n\n\n<div class=\"wp-block-mathml-mathmlblock\">\\[ \\tau = 4700 \\cdot 0,000001 = 0,0047s = 4,7 ms\\]<\/div>\n\n\n\n<p class=\"wp-block-paragraph\">Laikas super trumpas, kondensatorius pasikraus, tuomet rezistorius tiesiog ribos baz\u0117s srov\u0119.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Toliau tranzistorius Q1, geras, smagus Darlingtonas ma\u017eame korpuse, atsidaro ir prijungia minus\u0105 prie rel\u0117s K1 ir indikatoriaus LED1 su jo rezistoriumi R1. Rel\u0117s srov\u0117 9,1 mA, plius ~15 mA LEDukui, tranziukas tikrai i\u0161laikys. Rel\u0117s kontaktai laiko 1A srov\u0119, tod\u0117l saugiklis F1 irgi 1A. rel\u0117s kontakt\u0173 sujungimas toks, kad b\u016bt\u0173 toks kaip ir pseudo galvaninis atri\u0161imas nuo prietaiso, nes rel\u0117 perduoda grynai maitinimo plius\u0105 arba maitinimo minus\u0105, o ne, tarkim, minus\u0105 po tranzistoriaus. Taip i\u0161vengiame koki\u0173 nors dar ne\u017einom\u0173 niuans\u0173 valdomo prietaiso schemoje.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Schemos vaizdelis 2D ir 3D:<\/p>\n\n\n\n<figure class=\"wp-block-gallery aligncenter has-nested-images columns-default is-cropped wp-block-gallery-1 is-layout-flex wp-block-gallery-is-layout-flex\">\n<figure class=\"wp-block-image size-large\"><a href=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161554.png\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"437\" data-id=\"5859\" src=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161554-1024x437.png\" alt=\"\" class=\"wp-image-5859\" srcset=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161554-1024x437.png 1024w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161554-300x128.png 300w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161554-768x327.png 768w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161554.png 1461w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/a><\/figure>\n\n\n\n<figure class=\"wp-block-image size-large\"><a href=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161537.png\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"564\" data-id=\"5861\" src=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161537-1024x564.png\" alt=\"\" class=\"wp-image-5861\" srcset=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161537-1024x564.png 1024w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161537-300x165.png 300w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161537-768x423.png 768w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161537-1536x846.png 1536w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161537-2048x1128.png 2048w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/a><\/figure>\n\n\n\n<figure class=\"wp-block-image size-large\"><a href=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161613.png\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"440\" data-id=\"5862\" src=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161613-1024x440.png\" alt=\"\" class=\"wp-image-5862\" srcset=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161613-1024x440.png 1024w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161613-300x129.png 300w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161613-768x330.png 768w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161613.png 1455w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/a><\/figure>\n\n\n\n<figure class=\"wp-block-image size-large\"><a href=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161457.png\"><img loading=\"lazy\" decoding=\"async\" width=\"1024\" height=\"489\" data-id=\"5860\" src=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161457-1024x489.png\" alt=\"\" class=\"wp-image-5860\" srcset=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161457-1024x489.png 1024w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161457-300x143.png 300w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161457-768x367.png 768w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161457-1536x734.png 1536w, https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Ekrano-kopija-2025-02-04-161457-2048x979.png 2048w\" sizes=\"auto, (max-width: 1024px) 100vw, 1024px\" \/><\/a><\/figure>\n<\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><a href=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Dimeris-EasyEDA.zip\" data-type=\"link\" data-id=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/Dimeris-EasyEDA.zip\" target=\"_blank\" rel=\"noreferrer noopener\">EsayEDA failiukai (SCH ir PCB) yra \u010dia<\/a>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Toliau veikimo bandymai ir \u0161iek tiek matavim\u0173.<\/p>\n\n\n\n<figure class=\"wp-block-video aligncenter\"><video height=\"1080\" style=\"aspect-ratio: 1920 \/ 1080;\" width=\"1920\" controls src=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/VID20250204081732.mp4\"><\/video><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">I\u0161 LED matosi, kad tranzistorius ka\u017ekiek dirba ir linijiniame re\u017eime, bet srov\u0117s ma\u017eos, trukm\u0117 nedidel\u0117, tai b\u0117dos su tuo nebus. Galima b\u016bt\u0173 prid\u0117ti \u0160mito triger\u012f, tuomet linijinio re\u017eimo nebeb\u016bt\u0173.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Eigoje fotorezistorius pakeistas \u012f <a href=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/PGM5506-MP.pdf\" data-type=\"link\" data-id=\"https:\/\/www.dclabs.lt\/dainiaus\/wp-content\/uploads\/2025\/02\/PGM5506-MP.pdf\" target=\"_blank\" rel=\"noreferrer noopener\">PGM5506-MP<\/a> &#8211; nes korpusas 5,5 mm, vietoje 12 mm.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Labai trumpas, greitas projektukas, atsirad\u0119s d\u0117l paprasto poreikio. Ma\u0161inose be dienos \u0161viesos lemp\u0173 privaloma dienos metu va\u017eiuoti \u012fjungus artim\u0173j\u0173 \u0161vies\u0173 lempas, tod\u0117l audio sistemos grotuvas galvoja, kad dabar naktis ir pritemdo savo displ\u0117j\u0173. Saul\u0117t\u0105 dien\u0105 jame beveik nieko ir nebesimato, plius \u012fjungiamas naktinis re\u017eimas, pavyzd\u017eiui, mygtuk\u0173 ap\u0161vietimas. Tas ypa\u010d galioja pakeitus gamyklin\u0117 automobilio grotuv\u0105 \u012f&#8230;<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[9,4],"tags":[],"class_list":["post-5828","post","type-post","status-publish","format-standard","hentry","category-auto","category-elektronika"],"_links":{"self":[{"href":"https:\/\/www.dclabs.lt\/dainiaus\/wp-json\/wp\/v2\/posts\/5828","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.dclabs.lt\/dainiaus\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.dclabs.lt\/dainiaus\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.dclabs.lt\/dainiaus\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/www.dclabs.lt\/dainiaus\/wp-json\/wp\/v2\/comments?post=5828"}],"version-history":[{"count":33,"href":"https:\/\/www.dclabs.lt\/dainiaus\/wp-json\/wp\/v2\/posts\/5828\/revisions"}],"predecessor-version":[{"id":6075,"href":"https:\/\/www.dclabs.lt\/dainiaus\/wp-json\/wp\/v2\/posts\/5828\/revisions\/6075"}],"wp:attachment":[{"href":"https:\/\/www.dclabs.lt\/dainiaus\/wp-json\/wp\/v2\/media?parent=5828"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.dclabs.lt\/dainiaus\/wp-json\/wp\/v2\/categories?post=5828"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.dclabs.lt\/dainiaus\/wp-json\/wp\/v2\/tags?post=5828"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}